Testing Markdown <strong>yo</strong>. python [n for n in range(0,8)]

It must be in easy category...

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Not so hard

Makes you search for what it is, how to do it, and where to do it. good for newbies like me

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easy

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For some unmarried people like me, it gets really difficult to find a partner beyond 40. Is that what that means?

For some unmarried people like me, it gets really difficult to find a partner beyond 40. Is that what that means?

It's easy. But thak, very nice program

very nice basic challenge

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not good even for noobs

To easy

easy pisy!!!

Simple and yet still fun.

MEX M=H

Nice and easy, good for warming up =)

I liked the train of thought, definitely would leave some in the dark

Kinda easy. Perfect to start learning CTF. Thank you so much ^w^

Simply google some things

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hint: what kind of encoding can it be?

Pretty easy if you know what you're looking at and looking for.

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Muy bueno para la identificacion de sistemas numericos

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easy but i like it anyway

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burp suite worked for it.

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This was the first challenge I solved immediately and now I feel like a super hacker Hahaha.

took me some time

Good

use hxd

Good

this one is too easy

Extremely easy, good for begginers.

Great beginner crypto stuff.

nice

took me 7 seconds

Very easy

it was easy good for beginners like me

It's east but take me some time because I want do this in python and I still learn it

today i learned that my javascript skills are rusty af

Love Cyberchef..

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damn this is in mr.robot

easy ones are good for my ego today, thank you.

easy ones are good for my ego today, thank you.

49 20 6c 69 6b 65 64 20 69 74 0a

Dead Easy! Good for beginners.

Understeand how computer transform numbers to letters and some common logic to solve

ASCII decoder is a great help to solve this problem...

Python3 solution

ans_list = [] orig = '41 42 43 54 46 7B 34 35 43 31 31 5F 31 35 5F 55 35 33 46 55 4C 7D' arr_of_hex = list(map(str, orig.split())) for hex_val in arr_of_hex: ... bytes_object = bytes.fromhex(hex_val) ... ascii_string = bytes_object.decode("ASCII") ... ans_list.append(ascii_string) ans = ''.join(map(str, ans_list)) print(ans)

just google hex to text (:

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So easy for me

Just know your ciphers

that was a easy one

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geez easy challenges are like not even challenges and anything above easy is hell

Good for beginners

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this is hex boyssss! l.'O'.l

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co do cholery?! O czym zapomniałem?! Hex, ACSII, ABCTF{4SC11_15_U53FUL}!!! Panie autor o co tu chodzi? Czemu wyskakuje mi niepoprawna flaga?

really easy, comments tips really helped!