[REDACTED] This comment is only shown to users who have solved this challenge.

[REDACTED] This comment is only shown to users who have solved this challenge.

Simple and fun !

excellent programming CTF for beginners

its simple program write script to read the file an count that line which is its one divisible by 2 OR its zeros divisible by 3 simple use mod

[REDACTED] This comment is only shown to users who have solved this challenge.

[REDACTED] This comment is only shown to users who have solved this challenge.

I know how I can solve the problem, but what is the flag exactly? It's not explained how the flag should be formulated.

[REDACTED] This comment is only shown to users who have solved this challenge.

[REDACTED] This comment is only shown to users who have solved this challenge.

[REDACTED] This comment is only shown to users who have solved this challenge.

Helped brush up on my vim skills

[REDACTED] This comment is only shown to users who have solved this challenge.

[REDACTED] This comment is only shown to users who have solved this challenge.

I got the answer but what format am i supposed to submit it in????

This is a really great challenge in my opinion.

I used c++ and the hardest part was to put space int the end of every line.

I used c++ and the hardest part was to put space int the end of every line.

[REDACTED] This comment is only shown to users who have solved this challenge.

dobra nie chwalcie się tak zjeby że rozwiązaliście łatwe zadanie

[REDACTED] This comment is only shown to users who have solved this challenge.

nice programming, using python code

I used regex with node.js ```const fs = require('fs') var text = fs.readFileSync('./data.dat','utf8')

function count0(bin){ var arr = bin.match(/(0)/g); return arr ? arr.length : 0; } function count1(bin){ var arr = bin.match(/(1)/g); return arr ? arr.length : 0; }

var binArray = text.split('\n') var succArray = []

binArray.forEach((bin) => { var zeros = count0(bin); var ones = count1(bin); if(ones % 2 == 0){ succArray.push(bin); } else if(zeros % 3 == 0){ succArray.push(bin); } }); console.log(succArray.length)```

[REDACTED] This comment is only shown to users who have solved this challenge.

[REDACTED] This comment is only shown to users who have solved this challenge.

good one for file operation

[REDACTED] This comment is only shown to users who have solved this challenge.

v cool. needed to remind myself how to read files in py, because i didn't want to do it in bash

whats the flag format??

Yeah! Excellent task for the beginner. I'm pleased :D

[REDACTED] This comment is only shown to users who have solved this challenge.

[REDACTED] This comment is only shown to users who have solved this challenge.

[REDACTED] This comment is only shown to users who have solved this challenge.

[REDACTED] This comment is only shown to users who have solved this challenge.

[REDACTED] This comment is only shown to users who have solved this challenge.

[REDACTED] This comment is only shown to users who have solved this challenge.

multiple ways to solve this one.

multiple ways to solve this one.

[REDACTED] This comment is only shown to users who have solved this challenge.

simple, but first you need to understand the quest

``` print(Test Markdown

```

''' print("Markdown Test")

'''

It's a good one

TIP for people who are stuck:

I didn't read the question carefully so I took a lot of time figuring out what was wrong with my answer when I didn't read the question properly. It's asking if the 0 is a multiple of 3 OR if its a multiple 2

[REDACTED] This comment is only shown to users who have solved this challenge.

I did it with Java and the code is a bit longer, but it does the work

[REDACTED] This comment is only shown to users who have solved this challenge.

[REDACTED] This comment is only shown to users who have solved this challenge.

You can solve this with a quick python script. Don't forget the OR

[REDACTED] This comment is only shown to users who have solved this challenge.

[REDACTED] This comment is only shown to users who have solved this challenge.

Standard

User nodejs help const fs = require('fs'); fs.readFile('C:/Users/ASUS/desktop/data.dat', "utf8", (err, data) => { data = data.split("\n") <br /> var x = 0 for(var i = 0 ; i < data.length ; i ++){ if( data[i] % 3 == 0 || data[i] %2 == 0){ x = x+1 } } console.log(x); }); result : 7644 Howww

Yess i can do it with NODE.JS xD ----> const fs = require('fs'); fs.readFile('C:/Users/ASUS/desktop/data.dat', "utf8", (err, data) => { data = data.split("\n") <br /> var x = 0 <br /> for(var i = 0 ; i < data.length ; i ++){ <br /> var dalam1Line = data[i] , angka0 = 0 , angka1 = 0; for (var z=0; z < dalam1Line.length; z++){ if (dalam1Line[z] == 0) angka0++; } for (var z=0; z < dalam1Line.length; z++){ if (dalam1Line[z] == 1) angka1++; } <br /> if( angka0 % 3 == 0 || angka1 % 2 == 0){ x++ } } console.log(x); });

without knowing literally anything abount hacking/in this case programming, this took me 3 days straight, really fun challange!

cannot download the file. MegaGay is making me wait 45 minutes

cool

with open('data.dat') as f: lines = [line.rstrip() for line in f] cnt = 0 for line in lines: if line.count("0") % 3 == 0 or line.count("1") % 2 == 0: cnt += 1 print(cnt)

[REDACTED] This comment is only shown to users who have solved this challenge.

Use the printf() function.

Lol I dont know how to code in python, It took me so long XD

[REDACTED] This comment is only shown to users who have solved this challenge.

[REDACTED] This comment is only shown to users who have solved this challenge.

nice python train :)

did in c++, was fun :)

Nice Challenge

If anyone want to get my solution then it is here ""https://github.com/root-ji218at/ctflearn.com/tree/master/Easy/Programming/Simple%20Programming"

here's my solution python count = 0; for line in open("data.dat", "r").readlines(): zero = 0 one = 0 for i in line: if i == '0': zero += 1 elif i == '1': one += 1 if zero % 3 == 0 or one % 2 == 0: count += 1 print(count)

[REDACTED] This comment is only shown to users who have solved this challenge.

[REDACTED] This comment is only shown to users who have solved this challenge.

validline = 0 with open("./data.dat","r")as f: for line in f: ocounter = 0 icounter = 0 for char in line: if char == "0": ocounter += 1 elif char == "1": icounter += 1 if ocounter %3 == 0 or icounter % 2 == 0: validline +=1 print(validline)

[REDACTED] This comment is only shown to users who have solved this challenge.

P

excellent for beginners

Hey @intelagent, I can't do it! Please help me out. Either script isn't working or giving an error :(

fun item made me wind back my python knowledge