Hard Live

Skynet Is (Almost) Taking Over

160 points

320 Solves

Cryptography

bobbyjives

Community Rating: 4.50 / 5

Headline

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Skynet is using a very small list of primes for RSA style encryption purposes. In fact their list is only the size of the smallest odd prime. One of the robots sent a message to three other robots. These are futuristic robots with the ability to use quantum computing and so they don't mind prime factoring huge numbers.You can't do that though. Find out what message the robot sent to his friends. Flag is in flag{} format. https://mega.nz/#!7WZg2I5I!UiyBukv8_IjartojnY86nhN5jsQFKE4tPCEF1lPqsQ8

First 10 Solvers

Rank Username
1 landofleet
2 entropy
3 thebadgod
4 redcode
5 zipzop
Rank Username
6 pedro
7 kronos
8 blakeks4711
9 thekidofarcrania moderator badge
10 vidar

Comments

    • michaelmichael

      0.0

      Cool challenge... gmpy2 is helpful. Couldn't factordb n2 and n3, but was able to solve the third prime the hard way

    • chokocheng

      0.0

      4 minutes solve this challenge. Why there is alot primes but first one is the key :D

    • elliot_pwn

      0.0

      The list of primes they are using is too small ;)

    • karmanyaahm

      0.0

      really not worth 160 points, but overall good problem

    • noother

      Protected 0.0

      [REDACTED] This comment is only shown to users who have solved this challenge.

      • Rivit

        Protected 0.0

        [REDACTED] This comment is only shown to users who have solved this challenge.

    • elejudgx9

      Protected 0.0

      [REDACTED] This comment is only shown to users who have solved this challenge.

    • IT_Oracle

      0.0

      A very fun classic RSA challenge! I enjoyed it a lot ^-^

      • Celebrity

        0.0

        i decrypted c1 but when i try to factorize n2 , n3 there are no factor shown plz help me...

        • IT_Oracle

          0.0

          All the ciphers decrypt to the same thing (the flag). Maybe you haven't converted the flag to the proper form...? Try using cyberchef. If you have further trouble, follow the reddit link on my profile and leave a post there.